A #5.95*g# mass of potassium bromide were dissolved in #400*cm^3# water ... what was the concentration of the solution in #mol*L^-1#?

1 Answer
Jul 14, 2017

Answer:

Approx. #0.1*mol*L^-1#......................

Explanation:

We use the quotient.....#"Molarity"-="Moles of solute"/"Volume of solution"#, and we know that #1*cm^3-=1*mL-=10^-3*L#......

And thus #"Molarity"=((5.95*g)/(119.0*g*mol^-1))/(400*cm^3xx10^-3*L*cm^-3)#

#=0.125*mol*L^-1# with respect to #KBr#. What are the concentrations with respect to #K^+# and #Br^-#? Are the units I use correct?