Question

Question #21724

Answer 1

The basicity of `H_2SO_4` is 2.

Molarity of `H_2SO_4` is 0.1M

So its normalty will be `0.2N`

Again

The basicity of `NaOH` is 1.

Molarity of `NaOH` is 0.1M

So its normalty will be `0.1N`

Now 100mL 0.1M `H_2SO_4` or 0.2N `H_2SO_4equiv` 20mL `1N` `H_2SO_4`

And 500mL 0.1M `NaOH` or 0.1N `NaOHequiv` 50mL `1N` `NaOH`

So `(50-20)=30mL` `1N` `NaOH` will be excess reactant left .

If the normality of final mixtureof volume (100+500)=600mL be `xN` then

`600xx x=30xx1`

`=>x=30/600=0.05N`