How does MnO_4^- ion behave in basic solution....?

Sep 16, 2017

In a (highly) basic medium, deep-red $\text{permanganate ion}$ is reduced to green $\text{manganate ion}$.....

Explanation:

And so we can write the one electron reduction.......

i.e. $M n \left(V I I +\right) \rightarrow M n \left(V I +\right)$

$M n {O}_{4}^{-} + {e}^{-} \rightarrow M n {O}_{4}^{2 -}$

And so we plumb for $B$.....i.e. $158.03 \cdot g \cdot m o {l}^{-} 1$