How does #MnO_4^-# ion behave in basic solution....?

1 Answer
Sep 16, 2017

Answer:

In a (highly) basic medium, deep-red #"permanganate ion"# is reduced to green #"manganate ion"#.....

Explanation:

And so we can write the one electron reduction.......

i.e. #Mn(VII+) rarrMn(VI+)#

#MnO_4^(-) + e^(-) rarr MnO_4^(2-)#

And so we plumb for #B#.....i.e. #158.03*g*mol^-1#