What is the oxidation state of #"H"_2"S"_2"O"_2"#?

1 Answer
Jul 22, 2017

Answer:

The oxidation state of the molecule is #0#.

Refer to the explanation below.

Explanation:

The overall oxidation state for a neutral compound always equals zero.

The oxidation numbers for each element are indicated below.

Hydrogen

The oxidation number of hydrogen in this case is #+1#. Since there are two hydrogen atoms the total oxidation number is #2xx+1=+2#

#stackrel(+2)"H"_2#

Oxygen

The oxidation number of oxygen is #-2#. Since there are two oxygen atoms, the total oxidation number for oxygen is #2xx-2=-4#.

#stackrel(-4)"O"_2#

Sulfur

The oxidation number of sulfur can be determined from the oxidation numbers for hydrogen and oxygen. The combined oxidation numbers for hydrogen and oxygen are #+2+(-4)=-2#.

Since the overall oxidation number of a neutral compound must be zero, the total oxidation number for sulfur in this compound must be #+2#, which means that each sulfur atom in the compound is #+1#, because #2xx+1=+2#.

#stackrel(+2)"S"_2#

The oxidation numbers for each element can be written above each element in the compound.

#stackrel(+2)"H"_2""stackrel(+2)"S"_2""stackrel(-4)"O"_2#