How many molecules, and how many ATOMS, are present in a #1*g# mass of nitrogen gas?

1 Answer
Jul 23, 2017

Answer:

Of dinitrogen, there are #1/28xxN_A# molecules..., where #N_A="Avogadro's Number"#, i.e. #N_A=6.022xx10^23*mol^-1#

Explanation:

And the number of nitrogen atoms is #1/14*N_A#.

#N_A="Avogadro's number"#, #=6.022xx10^23*mol^-1#.

Why use such an absurdly large number? Well, if we got #N_A# #"hydrogen atoms"# we have a mass of #1*g# of hydrogen precisely. We got #1*g# of dinitrogen.......

And thus we got..........

#(1*g)/(28.0*g*mol^-1)xxN_A=??"nitrogen molecules"#.....

#(1*g)/(14.0*g*mol^-1)xxN_A=??"nitrogen atoms"#