What molar quantity of gas occupies a volume of $25L$ under a pressure of $742kPa$ at a temperature of $295*K$ ?

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Answer 1 · 2017-07-24T19:13:28

WE assume ideality, and we get approx. $8*mol$ ....

We use the Ideal Gas Equation, and solve for $n$ ...

$n=(PV)/(RT)=(742*cancel(kPa)xx25*cancelL)/(8.314*(cancelL*cancel(kPa))/(mol*cancelK)*295*cancelK)$

$~=8*1/(mol^-1)=8*1/(1/(mol))=8*mol$

What molar quantity of gas occupies a volume of 25*L25*L under a pressure of 742*kPa742*kPa at a temperature of 295*K295*K?