# What molar quantity of gas occupies a volume of 25*L under a pressure of 742*kPa at a temperature of 295*K?

WE assume ideality, and we get approx. $8 \cdot m o l$....
We use the Ideal Gas Equation, and solve for $n$...
$n = \frac{P V}{R T} = \frac{742 \cdot \cancel{k P a} \times 25 \cdot \cancel{L}}{8.314 \cdot \frac{\cancel{L} \cdot \cancel{k P a}}{m o l \cdot \cancel{K}} \cdot 295 \cdot \cancel{K}}$
$\cong 8 \cdot \frac{1}{m o {l}^{-} 1} = 8 \cdot \frac{1}{\frac{1}{m o l}} = 8 \cdot m o l$