# Find the equation of parabola whose axis of symmetry is #x=-3# and passes through points #(-1,3)# and #(2,-5)#?

##### 1 Answer

Jul 24, 2017

#### Answer:

Please see below.

#### Explanation:

Given that the axis is

Now use the two points given to get:

From

From

Replace

Using

The equation is

If course, there are other ways to write the answer.

graph{(y+8/21(x+3)^2-95/21)(x+3)((x+1)^2+(y-3)^2-0.02)((x-2)^2+(y+5)^2-0.02)=0 [-12, 12, -6, 6]}