Question #2f05d

Jul 25, 2017

The balanced equation of the reaction.

$C a C {O}_{3} \left(s\right) + 2 H C l \to C {O}_{2} + C a C {l}_{2} + {H}_{2} O$

$\text{ "1mol" "" "2mol" "" "1"mol" equiv22.4L" at STP}$

100 mL $1 M \text{ } H C l$ solution contains $0.1 m o l H C l$

So $C {O}_{2}$ produced will be $\frac{0.1}{2} m o l$

$\mathmr{and} \frac{1}{2} \times 22.4 \times 0.1 L = 1.12 L$ at STP