# Question #3ed00

##### 1 Answer

The relative atomic mass of the element is

#### Explanation:

The idea here is that the **vapor density** of the chloride will help you determine its **molar mass**.

As you know, the vapor density of a gas is defined as the ratio that exists between the molar mass of the gas and the molar mass of hydrogen gas,

In your case, you have

#"VD" = "molar mass chloride"/"molar mass H"_2 = 59.5#

To make the calculations easier, you can use the approximation

#"molar mass H"_2 ~~ "2 g mol"^(-1)#

This means that you have

#"molar mass chloride" = 59.5 * "2 g mol"^(-1)#

#"molar mass chloride" = "119 g mol"^(-1)#

Now, you know that the *equivalent mass* of the metal is equal to **equivalent mass** of the metal, which is essentially the mass of **equivalent** of metal, tells you the mass of metal that combines directly with

So if

#"24 g metal + 35.5 g Cl = 59.5 g chloride"#

#"24 g metal + 35.5 g Cl = 59.5 g chloride"#

#color(white)(aaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaa)/color(white)(a)#

#"48 g metal + 71 g Cl = 119 g chloride"#

This means that **mole** of metal, which is equal to **equivalents** of metal, is equal to

#"molar mass metal = 48 g mol"^(-1)#

The *relative atomic mass* of the metal will thus be

#A_r = (48 color(red)(cancel(color(black)("g mol"^(-1)))))/(1color(red)(cancel(color(black)("g mol"^(-1))))) = 48#