Question #48d66

1 Answer
Aug 2, 2017

209350 Joules


For this you need the specific heat of water, which varies amongst other things with temperature. But say this constant is 4187. This means that to raise the temperature of 1kg of water with 1 Kelvin, we need 4187 Joules. So to raise 5kg of water with 10 Kelvin, we need

#4187*5*10 = 209350 "[J]"#