Question #88405

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Answer 1 · 2017-08-05T10:36:39

#0.01 mol# of #NaOH#

Reaction:

#CH_3COOH + NaOH -> CH_3COONa + H_2O#

# M = 0.1 M#

#V = 0.1 L #

#M = n/V#

#n= 0.01 mol #

#1 mol# of #CH_3COOH# requires #1mol # of #NaOH#

#:. 0.01mol # of #CH_3COOH# requires #1xx0.1 mol# of #NaOH#

#= 0.01 mol# of #NaOH#