Question

Question #0e3ac

Answer 1

Here's what I get.

Citric acid (`"H"_3"Cit"`) is a weak tricarboxylic acid with the chemical formula `"C"_6"H"_8"O"_7`.

Although the degree of dissociation depends on concentration, a reasonable rule of thumb is that citric acid is about 8 % ionized.

Thus, if you start with 1 mol of `"H"_3"Cit"`, the equilibrium solution will contain about `"0.92 mol H"_3"Cit, 0.08 mol H"^"+"`, and `"0.08 mol H"_2"Cit"^"-"`.

Thus 1 mol of `"H"_3"Cit"` produces 1.08 mol of "particles".

`"K"_2"HPO"_4` is an ionic substance.

It dissociates completely in solution:

`"K"_2"HPO"_4"(aq)" → "2K"^"+""(aq)" + "HPO"_4^"-""(aq)"`

The hydrogen phosphate ion is such a weak acid that we can ignore its ionization.

Thus 1 mol of `"K"_2"HPO"_4"` produces 3 mol of "particles" in solution.