# What volume of carbon dioxide would evolve from fierce heating of a 200*g mass of "calcium carbonate" on heating under standard conditions of "STP"?

Aug 18, 2017

Well, $\text{STP}$ specifies a temperature of $273.15 \cdot K$ and an absolute pressure of exactly 100 *kPa. I gets under $50 \cdot L$.

#### Explanation:

We interrogate the decomposition reaction....

$C a C {O}_{3} \left(s\right) + \Delta \rightarrow C a O \left(s\right) + C {O}_{2} \left(g\right) \uparrow$

And given complete decomposition we have a molar quantity of $\frac{200 \cdot g}{100.09 \cdot g \cdot m o {l}^{-} 1} = 2.0 \cdot m o l$ WITH RESPECT TO CALCIUM CARBONATE, AND CARBON DIOXIDE. And as you know this molar quantity also represents a (large!) number with respect to gaseous molecules.

And the volume expressed by this quantity is simply given by the old Ideal Gas equation..$V = \frac{n R T}{P}$

$\equiv \frac{2.0 \cdot m o l \times 0.0821 \cdot \frac{L \cdot a t m}{K \cdot m o l} \times 273.15 \cdot K}{\frac{100 \cdot k P a}{101.3 \cdot k P a \cdot a t {m}^{-} 1}}$

=??*L

And the number of molecules is simply 2*molxx6.022xx10^23*mol^-1=??