# How many electrons are found in a sample of dioxygen gas contained in a #"0.448 L"# container at STP?

##### 3 Answers

#### Explanation:

The no of electrons present in448 ml of O2 at STP

At STP conditions 1 mole of O2 gas =

So,

=

See.

#### Explanation:

Hence,

Here,

About

Assuming your definition of STP is

#PV = nRT# for pressure

#P# , volume#V# , mols#n# , temperature#T# , and universal gas constant#R# .

Rearranging, we get...

#V/n = (RT)/P#

#= (("0.082057 L"cdot"atm/mol"cdot"K")("273.15 K"))/"1 atm"#

#=# #"22.414 L/mol"#

So, with this molar volume, we compare ratios:

#"0.448 L"/("x mols") = "22.414 L"/"mol"#

#=> n_("O"_2) = "0.0200 mols"#

Each

#"0.0200 mols O"_2 harr "0.320 mols e"^(-)#

And thus, the number of electrons is given by

#color(blue)("Number of electrons") = "0.320 mols e"^(-) xx 6.0221413 xx 10^(23) "mol"^(-1)#

#= ulcolor(blue)(1.93 xx 10^(23)color(white)(.)"e"^(-))#