# Question #39731

Aug 19, 2017

Ans is (2)

#### Explanation:

${N}_{2} + 3 {H}_{2} \to 2 N {H}_{3}$

$3 m o l$ of ${N}_{2}$ and ${H}_{2}$ are taken

$\frac{3}{1} > \frac{3}{3}$

Clearly, ${H}_{2}$ is the limiting reagent in the reaction and so it will be fully consumed

Aug 19, 2017

(2) H2 will be fully consumed

#### Explanation:

Limiting Reagent : The reactant which is completely used up at the end of the reaction

Working :
Taking N2 to be the limiting reagent,

3 mol of N2 would require 9 (3x3) mol of H2 to fully react, but there is only 3 mol of H2 available for N2 to react with, therefore N2 is not the limiting reagent as there is not enough H2 provided for it to be completely used up.

Taking H2 to be the limiting reagent,

3 mol of H2 would require 1 (3/3) mol of N2 to fully react. As there is 3 mol of N2 available which is more than the required amount, H2 is the limiting reagent as it can get completely used up while N2 will remain in excess.

If H2 is the limiting reagent in the reaction of N2 + 3H2 -> 2NH3,

The amount of NH3 produced is 2 (3 / 3 x 2) mol according to the mole ratio.