# Question #dfec5

##### 1 Answer
Aug 21, 2017

Of course you can, but it is not a reasonable structure.

#### Explanation:

It looks as if you are trying to generate a resonance contributor for the azide ion, $\text{N"_3^"-}$.

What's wrong with a structure like this:

(Adapted from ResearchGate)

The two terminal nitrogen atoms do not have an octet!

You can draw three other structures in which all atoms have octets:

If it is possible to give all atoms an octet, a structure in which an atom does not have an octet is not a reasonable contributor.