Question #4fdb8

1 Answer
Oct 11, 2017

Remember: peroxide comes into play only when you add hydrobromic acid (HBr) to an alkene.

Explanation:

So, it does not matter if you use "peroxide" as a catalyst for addition of HCl in an alkene.

Now, bringing all the information into account, the reaction would follow a Markovnikov rule of addition.

Hence, the reaction would be rarr

CH_3CHCH_2+HClrarrCH_3CH(Cl)CH_3.

First of all the H^+ will attack the double bonded terminal carbon atom.

Then, it will form a relatively stable secondary carbonation.

The Cl^- will then attack the carbonation & form 2-Chloropropane.

Hope it Helps:)