Question #31fd3

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Answer 1 · 2017-08-22T09:07:29

infinity

#ln(x+1)=log_e"(x+1)#

#log_e"(x+1)=y#

#e^y=(x+1)#

#lim_"x-->oo"# #e^y=oo+1# #(oo+1=oo)#

#(e^y=oo)#

So, #y# should be infinity

y is the value of the limit..