How do you evaluate lim_(x-> 0) tanx/x?
2 Answers
Since
L = lim_(x->0) (sec^2x)/1
L = lim_(x->0) sec^2x
L = sec^2(0)
L = 1/cos^2(0)
L = 1
If we check the graph of the function
Hopefully this helps!
Aug 25, 2017
Please see below.
Explanation:
So,
= lim_(xrarro) sinx/x * lim_(xrarro)1/cosx
= 1*1/1 = 1