# Given constant pressure, how does the temperature change when a 500*cm^3 volume of gas at 373*K is cooled so that then volume reduces to 270*cm^3?

Old Charles' Law holds that ${V}_{1} / {T}_{1} = {V}_{2} / {T}_{2}$ under conditions of constant pressure......
We solve for ${T}_{2} = {V}_{2} / {V}_{1} \times {T}_{1} = \frac{270 \cdot c {m}^{3}}{500 \cdot c {m}^{3}} \times 373 \cdot K$
$= 201.5 \cdot K$