Given constant pressure, how does the temperature change when a #500cm^3# volume of gas at #373K# is cooled so that then volume reduces to #270*cm^3#?

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Answer 1 · 2017-08-28T13:59:48

Old Charles' Law holds that #V_1/T_1=V_2/T_2# under conditions of constant pressure......

We solve for #T_2=V_2/V_1xxT_1=(270*cm^3)/(500*cm^3)xx373*K#

#=201.5*K#

Clearly the temperature has to drop to reduce the volume so substantially.

Given constant pressure, how does the temperature change when a #500*cm^3# volume of gas at #373*K# is cooled so that then volume reduces to #270*cm^3#?