# Question #a6092

This is overly convoluted. A quicker way to do this is to use $\frac{1.61 k m}{m i}$.
$109 m i \cdot \frac{5280 f t}{m i} \cdot \left(12 \text{in")/(ft) * (2.54cm)/("in}\right) \cdot \frac{m}{{10}^{2} c m} \cdot \frac{k m}{{10}^{3} m} \approx 174 k m$