# If the molar mass of a material is 147.01*g*mol^-1, what mass of the material is required for a 1*L volume of a 0.1*mol*L^-1 solution?

Aug 29, 2017

We use the definition of concentration......$\text{Concentration"="Moles"/"Volume}$.

And we get a required mass of $14.7 \cdot g$.

#### Explanation:

And thus $\text{moles"="volume"xx"concentration}$

We require.....$1 \cdot L \times 0.1 \cdot m o l \cdot {L}^{-} 1 = 0.1 \cdot m o l$.

And now we simply multiply this molar quantity by the molar mass, i.e. $0.1 \cdot m o l \times 147.01 \cdot g \cdot m o {l}^{-} 1 = 14.7 \cdot g$.....