If the molar mass of a material is #147.01*g*mol^-1#, what mass of the material is required for a #1*L# volume of a #0.1*mol*L^-1# solution?

1 Answer
Aug 29, 2017

Answer:

We use the definition of concentration......#"Concentration"="Moles"/"Volume"#.

And we get a required mass of #14.7*g#.

Explanation:

And thus #"moles"="volume"xx"concentration"#

We require.....#1*Lxx0.1*mol*L^-1=0.1*mol#.

And now we simply multiply this molar quantity by the molar mass, i.e. #0.1*molxx147.01*g*mol^-1=14.7*g#.....