Question

How do we represent the reduction of `"dichromate"` to `Cr^(3+)`?

Answer 1

We gots a formal reduction of `Cr(VI+)` to `Cr(III+)`....

Explanation:

And as always we represent the reduction by conserving mass and charge, and introducing electrons as particles of convenience.....

And thus....

`underbrace(Cr_2O_7^(2-))_"orange red" +14H^(+) +6e^(-) rarr2Cr^(3+) +7H_2O`

Charge is balanced, and mass is balanced, so tick....

And what would we see in such a reduction? Orange-red dichromate is reduced to the green chromic ion.....`underbrace(Cr^(3+))_"green"`