# How do we represent the reduction of "dichromate" to Cr^(3+)?

Aug 31, 2017

We gots a formal reduction of $C r \left(V I +\right)$ to $C r \left(I I I +\right)$....

#### Explanation:

And as always we represent the reduction by conserving mass and charge, and introducing electrons as particles of convenience.....

And thus....

${\underbrace{C {r}_{2} {O}_{7}^{2 -}}}_{\text{orange red}} + 14 {H}^{+} + 6 {e}^{-} \rightarrow 2 C {r}^{3 +} + 7 {H}_{2} O$

Charge is balanced, and mass is balanced, so tick....

And what would we see in such a reduction? Orange-red dichromate is reduced to the green chromic ion.....${\underbrace{C {r}^{3 +}}}_{\text{green}}$