How do we represent the reduction of #"dichromate"# to #Cr^(3+)#?

1 Answer
Aug 31, 2017

Answer:

We gots a formal reduction of #Cr(VI+)# to #Cr(III+)#....

Explanation:

And as always we represent the reduction by conserving mass and charge, and introducing electrons as particles of convenience.....

And thus....

#underbrace(Cr_2O_7^(2-))_"orange red" +14H^(+) +6e^(-) rarr2Cr^(3+) +7H_2O#

Charge is balanced, and mass is balanced, so tick....

And what would we see in such a reduction? Orange-red dichromate is reduced to the green chromic ion.....#underbrace(Cr^(3+))_"green"#