# Question #3a8f2

And thus, we got $6 \left(O\right) \cdot e + 3 \left\{H\right\} \cdot e - 1 \cdot e$ (to account for the positive charge, and we have to distribute 4 electron pairs around the central oxygen, $: \stackrel{+}{O} {H}_{3}$; because oxygen has a share of only 5 valence electrons, (lone pair + 3 bonding electrons) is has a total electron count of 7 electron, with 2 inner core electrons; 7 electrons in total and therefore a formal positive charge.