# What mass of carbon dioxide will result from the decomposition of 300*g of calcium carbonate?

Sep 1, 2017

Approx. $132 \cdot g$ of gas should be evolved.

#### Explanation:

We need a stoichiometric equation to represent the equation, and inform our calculation.....

$C a C {O}_{3} \left(s\right) + \Delta \rightarrow C a O \left(s\right) + C {O}_{2} \left(g\right) \uparrow$

And thus 1 equiv of calcium carbonate decomposes with heat to give 1 equiv of calcium oxide, and 1 equiv of carbon dioxide.

And so we determine the molar quantities......

$\text{Moles of calcium carbonate} = \frac{300 \cdot g}{100.09 \cdot g \cdot m o {l}^{-} 1} = 3.00 \cdot m o l$

And thus we get THREE MOLES EACH of calcium oxide and carbon dioxide.......

"Mass of CaO"=3*molxx56.08*g*mol^-1=??*g

"Mass of carbon dioxide"=3*molxx44.01*g*mol^-1=??*g