# If the density of a material is 0.88*g*mL^-1, what is the material?

Sep 3, 2017

$\rho = \text{Mass"/"Volume} = \frac{8.184 \cdot g}{10.5 \cdot m L - 1.2 \cdot m L} = 0.88 \cdot g \cdot m {L}^{-} 1$.