# Solve for #h#: #V=1/3 pi r^2 h#?

##### 1 Answer

#### Answer:

Move terms that don't have

#### Explanation:

If we want to solve *inverses* of everything other than

#color(white)(=>)Vcolor(white)(xx 3/(pir^2))=1/3pir^2h#

#=>Vcolor(red)(xx 3/(pir^2))=1/3pir^2hcolor(red)(xx 3/(pir^2))#

The multiplication by

#=>Vxx 3/(pir^2)=1/color(orange)cancelcolor(black)(3)color(magenta)cancelcolor(black)(pir^2)h xx color(orange)cancelcolor(black)3/color(magenta)cancelcolor(black)(pir^2)#

#=> color(white)(V xx)(3V)/(pir^2)=color(white)(1/cancel3 cancel(pir^2))h#

Thus, our cone volume formula, when solved for

#h=(3V)/(pir^2)#