What volume of ammonia may be prepared from a #1*g# mass of dinitrogen gas?

1 Answer
Sep 9, 2017

Answer:

Approx. #1*L# of ammonia............

Explanation:

We need (i) a stoichiometric equation.....

#1/2N_2(g) + 3/2H_2(g)rightleftharpoonsNH_3(g)#

And (ii) we need equivalent quantities of dinitrogen gas.....

#-=(1.4*g)/(28.01*g*mol^-1)=0.050*mol# with respect to #N_2#.

Given the equation I can make AT MOST #0.100*mol# with respect to ammonia........Agreed?

Since an ideal gas has a molar volume at STP of #22.4*L*mol^-1# (or whatever your syllabus says), we gots a volume of....

#22.4*L*mol^-1xx0.05*mol~=1*L#