# What is the Lewis structure of nitrite ion, NO_2^(-)?

Well, we gots $5 \left(N\right) + 2 \times 6 \left(O\right) + 1 \left(\text{negative charge}\right)$ valence electrons to distribute....
And thus,...$O = \ddot{N} - {O}^{-}$; from left atom to right atom, there are 6, 5, and 7 valence electrons associated with each atom, and hence formal charges of $0 , 0 ,$ and $- 1$.
The electron pairs are distributed in a trigonal plane, but the geometry is bent with $\angle O - N - O > {120}^{\circ}$, due to the disproportionate influence of the nitrogen lone pair.....