How could you represent the reaction of copper metal with sulfuric acid?

1 Answer
Sep 10, 2017

Answer:

By consideration of redox reaction......

Explanation:

Copper is oxidized to copper sulfate.....

#Cu(s) rarr Cu^(2+) + 2e^-# #(i)#

Sulfuric acid is REDUCED to sulfur dioxide....

#H_2SO_4 +2H^(+) + 2e^(-) rarr SO_2(g)+2H_2O(l)# #(ii)#

And we takes #(i)+(ii)# to give......

#Cu(s) + H_2SO_4(aq) +2H^(+) rarr Cu^(2+) + SO_2(g)+2H_2O(l)#

You would really need to give this a good blast of heat to oxidize copper metal, which is fairly unreactive.....and sulfuric acid is non-oxidizing.