Question #210d9

1 Answer
Sep 12, 2017

Answer:

See below.

Explanation:

Here it is a conceptual approach.
my pleasure to supply
Here, We get #h=1/2g t^2# where #h# is the height of the house from the ground level, #g# is the gravitational acceleration and #t# is the time taken.

Hence ,we get #t=sqrt((2h)/g#
Putting the given value we get #t# is #sqrt((2xx60)/10)=3.46s#

Now we have to determine the distance covered in #X# axis.
As we have get the initial velocity of the egg(u) is #6.5m//s# and time taken to touch the ground is #3.46s#,hence the distance is
#(6.5xx3.46)m=22.52m#.
Here's the answer....
Enjoy physics...
Sorry for my mistake....