# Question 210d9

Sep 12, 2017

See below.

#### Explanation:

Here it is a conceptual approach.

Here, We get $h = \frac{1}{2} g {t}^{2}$ where $h$ is the height of the house from the ground level, $g$ is the gravitational acceleration and $t$ is the time taken.

Hence ,we get t=sqrt((2h)/g#
Putting the given value we get $t$ is $\sqrt{\frac{2 \times 60}{10}} = 3.46 s$

Now we have to determine the distance covered in $X$ axis.
As we have get the initial velocity of the egg(u) is $6.5 m / s$ and time taken to touch the ground is $3.46 s$,hence the distance is
$\left(6.5 \times 3.46\right) m = 22.52 m$.