Question

Question #5ae10

Answer 1

I tried this:

Explanation:

The two scales are related but in a slight complicated way (because the difference in intervals between fixed points of the two). Anyway, we have:

`"Temp. in Celsius"=5/9xx("Temp. in Farhenheit"-32)`

you need to insert `98.6` into the formula and evaluate the Temperature in Celsius.

[You should get `37^@C`]