# Question 5ae10

Sep 13, 2017

I tried this:

#### Explanation:

The two scales are related but in a slight complicated way (because the difference in intervals between fixed points of the two). Anyway, we have:

"Temp. in Celsius"=5/9xx("Temp. in Farhenheit"-32)#

you need to insert $98.6$ into the formula and evaluate the Temperature in Celsius.

[You should get ${37}^{\circ} C$]