How do I find the change in temperature of #"199.0 g"# of water that loses #"2793 J"# of heat?

1 Answer
David Drayer · Truong-Son N.
Sep 15, 2017

It goes down by 3.354 degrees C.

Explanation:

#"J"/("J"/("g"cdot""^@ "C")) = "g"^@ "C"#

# ("g"^@"C") / "g" = ""^@"C"#

So dividing the number of joules 2793 by the specific heat and then by the number of grams will give the change in degrees C:

#"2793 J"/("4.184 J/g"^@ "C") = "667.5 g"^@"C"#

#"667.5 g"^@"C" // "199.0 g" = 3.354^@ "C"#.

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