# How do I find the change in temperature of "199.0 g" of water that loses "2793 J" of heat?

Sep 15, 2017

It goes down by 3.354 degrees C.

#### Explanation:

$\text{J"/("J"/("g"cdot""^@ "C")) = "g"^@ "C}$

 ("g"^@"C") / "g" = ""^@"C"

So dividing the number of joules 2793 by the specific heat and then by the number of grams will give the change in degrees C:

$\text{2793 J"/("4.184 J/g"^@ "C") = "667.5 g"^@"C}$

$\text{667.5 g"^@"C" // "199.0 g" = 3.354^@ "C}$.