# Question #a117f

$4 A l {\left(C l {O}_{4}\right)}_{3} \left(s\right) \to 4 A {l}^{3 +} + 12 C l O {4}^{-}$
$16$ ions will form.
Write the formula representing the solvation of a single molecule of aluminum perchlorate. Multiply by a factor of $4$.