Question #13154

1 Answer
Sep 26, 2017

Final velocity v=24.54 m/s
distance Travels=65.51m

Explanation:

Initial velocity of snowmobile v_o=14 m/s
Acceleration a=3.1 m/s^2
time t=3.4 sec
Final Velocity v=?
Distance traveled s=?

To calculate Final Velocity
Using Newton's First equation of Motion
v=v_o +at
=>v=14+(3.1)(3.4)=14+10.54=24.54 m/s
Final Velocity v=24.54 m/s

To calculate travel distance
Using Newton's Third equation of Motion
v^2=v_o^2+2as
s=(v^2-v_o^2)/(2a)
s=((24.54)^2-(14)^2)/(2(3.1))=(602.21-196)/6.2=406.21/6.2=65.51m
s=65.51m