# Question a0de1

Oct 3, 2017

#### Explanation:

The wheel with a diameter of $30$inch overcomes a distance of ($\pi \times$diameter$\times$n revolutions)=$\pi \times 30 \times 240 = 7200 \pi$ inch

In this case the second wheel will also overcome a same distance i.e, $7200 \pi$ inch.
The diameter of the second wheel is $20$ inch hence its circumference will be $20 \times \pi = 20 \pi$ inch.

So the second wheel will have to complete $\frac{7200 \pi}{20 \pi} = 360$ revolutions...

Hope it helps...
Thank you...

Oct 28, 2017

The small wheel will revolve 360 times in the same distance.

#### Explanation:

These two wheels may be on one side of a wagon with the front steering wheels smaller than the load carrying wheels at the back.

Then in the same distance:

The $30 i$ wheel turns $240$ times for a distance of $30 i \left(240\right)$.
The $20 i$ wheel turns $T$ times for a distance of 20i(T) .

And: $\left(30 i\right) \left(240\right) = 20 i T$

$720 \cancel{i} = 20 \cancel{i} T$

$360 = T$