Question #a4966
1 Answer
Two electrons.
Explanation:
As you know, the principal quantum number,
In your case, you have
#n = 3#
which means that your electrons are going to be located in the third energy shell, i.e. on the third energy level.
Now, notice that the problem provides you the value of the magnetic quantum number,
In your case, you have
#m_l = +1#
so your goal now is to figure out how many subshells located on the third energy level can hold an orbital designated by that value of the magnetic quantum number.
As you know, the identity of the energy subshell in which an electron is located is given by the angular momentum quantum number,
#l = {0, 1, ..., n-1}#
In your case, you have
#l = {0, 1, 2}#
So the third energy shell can hold a total of
#l = 0 -># the s subshell#l=1 -># the p subshell#l = 2 -># the d subshell
Now, the magnetic quantum number depends on the angular momentum quantum number as follows
#m_l = {-l, - (l-1), ..., -1, 0, 1, ..., (l-1), l}#
This means that an orbital described by
#l = 1 implies m_l = {-1, 0, +1}# #l = 2 implies m_l = {-2, - 1, 0, +1, +2}#
This means that a total of
Finally, the problem gives you a value for the spin quantum number,
As you know, an orbital can hold a maximum of two electrons of opposite spins, i.e. one spin-up electron and one spin-down electron.
This means that a total of
#n =3, color(blue)(l = 1), m_l = +1, m_s = +1/2# This set describes an electron located on the third energy level, in the
#3color(blue)(p)# subshell, let's say in the#3p_y# orbital, that has spin-up
#n =3, color(red)(l = 2), m_l = +1, m_s = +1/2# This set describes an electron located on the third energy level, in the
#3color(red)(d)# subshell, let's say in the#3d_(yz)# orbital, that has spin-up