Question #254f6
2 Answers
Explanation:
#"the "color(blue)"sum to n terms"# for a geometric series is.
#•color(white)(x)S_n=(a(r^n-1))/(r-1)#
#"where a is the first term and r the "color(blue)"common ratio"#
#r=(a_2)/(a_1)=(-6)/2=-3#
#rArrS_7=(2((-3)^7-1))/(-4)#
#color(white)(rArrS_7)=(2xx-2188)/(-4)=1094#
Answer is
Explanation:
Given the geometric series is:
Let,
So, common multiplier
Now, Let a term of the sequence be
So,
Now, Let sum of the series up to
So, sum upto
Hope it Helps!!