Question #00934

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Answer 1 · 2017-10-15T09:40:15

The point is #(0,-3)#.

The equation of the given straight line is #y=4x-3#.

Let, the straight line cut a point #(0,p)# on the Y-axis.

The abscissa of the point will be zero, since it is a point on to the Y-axis.

Now, substituting the coordinates in the equation we get,

#p=(4xx0)-3#

#:.p=-3#.

Therefore, the straight line cuts Y-axis at the point #(0,-3)#. (Answer).

Hope it Helps:)