After rolling four dice, what is the probability that all four dice show different numbers?

1 Answer
Oct 17, 2017

#"P"(E)=5/18#

Explanation:

Let #E# be the event 'All four dice show different numbers' and #S# be the sample space of the experiment. Then #absS=6^4# and #"P"(E)=absE"/"absS.#

In order to find #absE#, we can consider the four dice rolls independently. On the first roll, there is no risk of duplicating any previous roll (since there aren't any), so there are 6 acceptable outcomes. For the second roll, we want to avoid whatever the first roll was, so there are 5 acceptable outcomes.

If we keep going, assuming we keep rolling different numbers, then on roll three, there are 4 acceptable outcomes, and on roll four, there are 3 acceptable outcomes. (As the roll counter goes up, the number of possible unique rolls goes down.)

Assuming independence of rolls, we get #absE=6 xx 5 xx 4 xx 3,# which gives #absE=360.#

Since #"P"(E)=absE/absS#, we get

#"P"(E)=360/6^4=60/216=5/18,#

which is approximately 27.78%.