Question

If `log_bx=2`, find `log_(1/b)x` and `log_b(1/x)`?

Answer 1

`log_(1/b)x=-2` and `log_b(1/x)=-2`

Explanation:

As `log_bx=2`, `b^2=x`

and `(1/b)^2=1/b^2=1/x`

or `x=(1/b)^(-2)` and hence `log_(1/b)x=-2`

We also have `b^(-2)=1/x`

hence `log_b(1/x)=-2`