Question #51f38

Oct 29, 2017

There are approximately $2.38$ moles of sodium bicarbonate in $\text{200 g}$.

Explanation:

We must first find the molar mass of sodium bicarbonate, ${\text{NaHCO}}_{3}$.

We do this as follows:

1) Find the molar mass of each element in the compound.

• $\text{Na = 22.99 g/mol}$
• $\text{H = 1.008 g/mol}$
• $\text{C = 12.01 g/mol}$
• $\text{O = 16.00 g/mol}$

2) Add up the molar masses to find the molar mass of the compound.

$1 \left(22.99\right) + 1 \left(1.008\right) + 1 \left(12.01\right) + 3 \left(16.00\right) = \text{84.008 g/mol}$

This means that each mole of sodium bicarbonate weighs about $84.008$ grams.

3) Divide the number of grams by the molar mass to find moles.

$\text{200 g"/"84.008 g/mol" = "2.38 moles}$

Note: Keep in mind that you have one significant figure for the mass of sodium bicarbonate!