Question #f5b48

2 Answers
Nov 5, 2017

= 390.8828 g H_2SO_4

Explanation:

2.4*10^24 mo H_2SO_4 ((1 mol H_2SO_4)/(6.022*10^23 mo H_2SO_4)) ((98.079 g H_2SO_4)/(1 mol H_2SO_4))
= 390.8828 g H_2SO_4

*mo is molecules

Nov 5, 2017

390.88 g of H_2SO_4

Explanation:

To solve this question we need to know the mole concept. As we know that,

1 mole = 6.022 X 10^23 "molecules"

And we also know that the molar mass of H_2SO_4 is 98.079 g/mol which means:

1 mole of H_2SO_4 = 98.079 g

By using the above two relations, we get:

6.022 X 10^23 "molecules" of H_2SO_4 = 98.079 g of H_2SO_4

or, 1 "molecules" of H_2SO_4 = frac(98.079 )(6.022 X 10^23) g of H_2SO_4

or , 2.4X10^24 "molecules" of H_2SO_4 = frac(98.079)(6.022 X 10^23) X 2.4X10^24 g of H_2SO_4 = 390.88 g of H_2SO_4

Therefore, 2.4X10^24 "molecules" of H_2SO_4 contain 390.88 grams of H_2SO_4.