Question #7f679

1 Answer
Feb 22, 2018

The maximum profit is $91 with 30 employees.

Explanation:

Let the amount of money be $y.

Given y=-0.1x^2+6x+1
y=-0.1(x^2-60x)+1
y=-0.1[(x-30)^2-900]+1
y=-0.1(x-30)^2+91

When x deviates from 30,
(x-30)^2>0
And the respective value of y will decrease.

Hence, to maximize the profit, x should be as close to (and should be) 30, which by substitution,

y=91