How many single substituted halides can be formed from (i) #"2-methylhexane"#, and (ii) #"3-methylhexane"#?

1 Answer
anor277
Jan 17, 2018

Well, let us look at the mono-halides of the two hexanes....

Explanation:

For #H_3C-CH_2CH(CH_3)CH_2CH_3#...I can form FOUR monohalide derivatives.... (I would probably do so from the substituted olefin)...

#1.# #H_3C-CH_2CX(CH_3)CH_2CH_3#;

#2.# #H_3C-CH_2CH(CH_2X)CH_2CH_3#;

#3.# #H_3C-CH_2CH(CH_3)C(H)(X)CH_3#;

#4.# #H_3C-CH_2CH(CH_3)CH_2CH_2X#....

For #H_3C-CH(CH_3)CH_2CH_2CH_3#...I can form SIX monohalide derivatives....

#1.# #XH_2C-CH(CH_3)CH_2CH_2CH_3#

#2.# #H_3C-CX(CH_3)CH_2CH_2CH_3#

#3.# #H_3C-CH(CH_2X)CH_2CH_2CH_3#

#4.# #H_3C-CH(CH_3)C(H)(X)CH_2CH_3#

#5.# #H_3C-CH(CH_3)CH_2C(H)(X)CH_3#

#6.# #H_3C-CH(CH_3)CH_2CH_2CH_2X#

And of course, these are just the structural isomers. I have not considered the geometric isomers, and enantiomers.... The premise of your question seems to be wrong. Anyway, you should write these out on a page in order to verify that I got the connectivity right.

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