A polynomial function with leading coefficient #a# has zeroes of multiplicity one at #x = -2# and #x = 1# and a zero of multiplicity two at #x = 2#. What is the equation of this polynomial function?

1 Answer
Nov 27, 2017

#y = a(x +2)(x - 1)(x - 2)^2# will be the equation, where #a# is a real number.

Explanation:

The zeroes of multiplicity #n# will have exponent #n#.

#y = a(x +2)(x - 1)(x - 2)^2#

Where #a# is the vertical stretch/compression. This will influence the placement of the y-intercept. I haven't specified the value of #a# because the y-intercept isn't given .

I'll leave you the task to multiply it out into standard form. If you don't know what standard form is take a look here:

Standard form of #(x - 3)(x - 2)# would be #x^2 - 5x + 6#, or the expanded version of the expression.

Hopefully this helps!