# Question #7c310

Nov 28, 2017

While the flow of electrons (current) is the same for both motors, the driving force (voltage potential) is $6. \overline{6}$ times greater in the $120$ VAC motor compared to that of the $18$ VDC motor.

#### Explanation:

The difference is evident in the first line of the question; the available power is much greater for the higher voltage engine.

As a result, its torque will also be significantly larger under similar operating conditions (speed, efficiency).

$\tau = \frac{I \cdot V \cdot E \cdot 60}{r \cdot 2 \pi}$

$\tau =$torque
$I =$current
$V =$voltage
$E =$efficiency
$r =$rpm