Question

What molar quantity is contained in a `552*mL` volume of `"CCl"_4(g)` at `100` `""^@C`, and a pressure of `1.01*atm`?

Answer 1

We solve for `n` in the Ideal Gas equation....and get a mass of approx. `3*g`...

Explanation:

The normal boiling point of `"carbon tetrachloride"` is `76.7` `""^@C`, and thus we assume that the `"carbon tet"` is present in the gaseous phase (the pressure is `1.01*atm`)....

`n=(PV)/(RT)=(1.01*atmxx552*mLxx10^-3*L*mL^-1)/(0.0821*(L*atm)/(K*mol)xx373.1*K)`

`=0.0182*mol`

And we multiply this molar quantity by the molar mass of `"carbon tet"`, i.e. `0.0182*molxx153.82*g*mol^-1=??*g`