Prove that #sqrt((1+sintheta)/(1-sintheta))=csctheta+costheta#?

1 Answer
Dec 6, 2017

It is #sectheta+tantheta# not #csctheta+costheta#

Explanation:

#sqrt((1+sintheta)/(1-sintheta))#

= #sqrt((1+sintheta)/(1-sintheta)xx(1+sintheta)/(1+sintheta))#

= #sqrt((1+sintheta)^2/(1-sin^2theta))#

= #sqrt((1+sintheta)^2/cos^2theta)#

= #(1+sintheta)/costheta#

= #1/costheta+sintheta/costheta#

= #sectheta+tantheta#