Question

Question #59d74

Answer 1

`6m` though some values of `m` will have a LCM of `n6m, ninZZ`

Explanation:

We first split the two numbers into their prime factors.

`12=2xx2xx3`
`3m=3xxm`

`12` has 3 factors, while `3m` has two factors.

An LCM must be divisible by both numbers. So we will take all facotrs while leaving out any duplicates:

`2xx2xx2xx3xx3xxm`

`LCM=2xx3xxm=6m` (Though some numbers will be a multiple of `6m`)

A graph can be found here: https://www.desmos.com/calculator/gdv8vbn9ed